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Sagot :
Given that the weight of the person is W = 740 N.
The weight can be calculated by the formula,
[tex]\begin{gathered} W=mg \\ m\text{ =}\frac{W}{g} \end{gathered}[/tex]Here, m is the mass of the person, g is the acceleration due to the gravity of the earth.
[tex]\begin{gathered} g\text{ = }\frac{GM}{R^2} \\ =\frac{9.81m}{s^2} \end{gathered}[/tex]Here, G is the universal gravitational constant.
M is the mass of the earth and R is the radius of the earth.
The mass of the person will be
[tex]\begin{gathered} m\text{ = }\frac{740}{9.81} \\ =75.43\text{ kg} \end{gathered}[/tex]Now, the new acceleration due to gravity is
[tex]\begin{gathered} g^{\prime}=\frac{2GM}{(4R)^2} \\ =\frac{2}{16}\times g \\ =1.226m/s^2 \end{gathered}[/tex]Now the new weight will be
[tex]\begin{gathered} W^{\prime}\text{ = m}\times g^{\prime} \\ =\text{ 75.43}\times1.226 \\ =92.477\text{ N} \end{gathered}[/tex]Thus, the new weight is 92.477 N.
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