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IR 1 sn Jason launched a rocket for a physics experiment. This equation can be used to find the height (h), in feet, of the rocket after t seconds. h = -16t2 + 288t + 8 How many seconds will it take for the rocket to reach the max height?

Sagot :

The given equation is,

[tex]h=-16t^2+288t+8[/tex]

For maximum height,

[tex]\begin{gathered} h^{\prime}(t)=0 \\ -32t+288=0 \\ t=9\text{ sec.} \\ h^{\doubleprime}(t)=-32<0 \end{gathered}[/tex]

Thus, t=9 second is the required time to reach maximum height.