[tex]\begin{gathered} sin\theta+cot\theta cos\theta=sin\theta+\frac{1}{tan\theta}cos\theta=sin\theta+\frac{cos\theta}{sin\theta}cos\theta \\ =sin\theta+\frac{cos^2\theta}{sin\theta} \\ \\ =\frac{sin^2\theta+cos^2\theta}{sin\theta}=\frac{1}{sin\theta} \\ \end{gathered}[/tex]
The answer is B
