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If you invest this money ($7,185.51 ) in an account that compounds monthly with an APR of 2.5%, how much will you have saved i) after 1 year? ii) after 3 years?

Sagot :

Explanation:

The principal is given below as

[tex]P=7185.81[/tex]

The APR is given below as

[tex]r=2.5\%=\frac{2.5}{100}=0.025[/tex]

Concept:

To figure out the the compund interest, we will use the formula below

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

For one year, we will have the amount be

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ n=12,t=1 \end{gathered}[/tex]

By substituting the values, we would have

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=7185.51(1+\frac{0.025}{12})^{1\times12} \\ A=7,185.51(1+\frac{0.025}{12})^{12} \\ A=7367.22 \end{gathered}[/tex]

Hence,

The amount ave after 1 year will be

[tex]A=7,367.22[/tex]

To calculate the amount for three years, we will have

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ n=12,t=3 \\ \end{gathered}[/tex]

By substituting the values, we will have

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=7185.51(1+\frac{0.025}{12})^{3\times12} \\ A=7,185.51(1+\frac{0.025}{12})^{36} \\ A=7744.54 \end{gathered}[/tex]

Hence,

The amount ave after 3 years will be

[tex]\begin{equation*} 7744.54 \end{equation*}[/tex]