From personal advice to professional guidance, IDNLearn.com has the answers you seek. Find the information you need quickly and easily with our reliable and thorough Q&A platform.
Sagot :
Step 1
All radiation decay follows first order kinetics as follows:
[tex]\text{A = A}_0xe^{-\lambda t}[/tex]λ = decay constant
t = time taken
A0 = initially present mass
A = mass present after t time
------------------
Step 2
Information provided:
12.3 y = half-life time = t 1/2
A0 = 48.0 mg
-------------------
Step 3
Procedure:
λ is calculated as follows:
[tex]\begin{gathered} t_{\frac{1}{2}\text{ }}=\text{ }\frac{ln2}{\lambda} \\ \lambda\text{ = }\frac{ln\text{ 2}}{12.3\text{ years}}=\text{ 0.056 1/y} \end{gathered}[/tex]Now,
From step 1:
[tex]\begin{gathered} A\text{ = 48.0 mg x }e^{-0.056\frac{1}{years}x\text{ 49.2 years}} \\ A\text{ = 3.05 mg} \end{gathered}[/tex]For t = 98.4 years => A = 0.194 mg
Answer:
What mass of the nuclide will remain after 49.2 y? 3.05 mg
And then after 98.4 y? 0.194 mg
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.
