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EVALUATE THE FOLLOWING:A) 85!/82!B) nC0C) nPnI GOT THIS AS MY ANSWER?A.592620B. 1C. 1Part C

Sagot :

To answer this question we need to remember that:

[tex]0!=1[/tex]

and that a permutation is defined as:

[tex]_nP_k=\frac{n!}{(n-k)!}[/tex]

Then, in this case we have:

[tex]_nP_n=\frac{n!}{(n-n)!}=\frac{n!}{0!}=\frac{n!}{1}=n![/tex]

Therefore, we have that:

[tex]_nP_n=n![/tex]

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