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Input data
Width = ?
Lenght = 5/6 ft
Area = 8 sq ft
The area of the rectangle can be written as the following equation
[tex]A=l\cdot w[/tex]To determine the width the equation will be
[tex]\begin{gathered} w=\frac{A}{l} \\ w=\frac{8}{\frac{5}{6}} \\ w=\frac{8\cdot6}{5} \\ w=\frac{48}{5} \\ w=9.6 \\ \end{gathered}[/tex]Width would be 9.6 ft.