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Sagot :
[tex]y(he+b)=d+z[/tex]
solve for y by dividing both sides by (he+b)
[tex]\begin{gathered} y\frac{\mleft(he+b\mright)}{\mleft(he+b\mright)}=\frac{d+z}{\mleft(he+b\mright)} \\ y=\frac{d+z}{(he+b)} \end{gathered}[/tex]to solve for e start by dividing by y on both sides
[tex]\begin{gathered} \frac{y(he+b)}{y}=\frac{d+z}{y} \\ he+b=\frac{d+z}{y} \end{gathered}[/tex]continue by substracting b on both sides
[tex]\begin{gathered} he+b-b=\frac{d+z}{y}-b \\ he=\frac{d+z}{y}-b \end{gathered}[/tex]divide by h on both sides to solve for e
[tex]\begin{gathered} \frac{he}{h}=\frac{1}{h}\cdot(\frac{d+z}{y}-b) \\ e=\frac{d+z}{hy}-\frac{b}{h} \end{gathered}[/tex]ANSWER
[tex]y=\frac{d+z}{(he+b)}[/tex][tex]e=\frac{d+z}{hy}-\frac{b}{h}[/tex].
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