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Solve 5ax + 3 ax = 4ax + 12 for x. Assume a + 0. A. x= 3a 3 O B. 1 c. F D. X= a a

Sagot :

So we have to solve the equation:

[tex]5ax+3ax=4ax+12[/tex]

Knowing that a isn't zero. Let's start:

[tex]\begin{gathered} 5ax+3ax=8ax=4ax+12 \\ 8ax-4ax=12 \\ 4ax=12 \end{gathered}[/tex]

Then, since a isn't zero we can divide the right side of the equation by 4a:

[tex]x=\frac{12}{4a}=\frac{3}{a}[/tex]

So correct option is B.

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