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Sagot :
So we have to solve the equation:
[tex]5ax+3ax=4ax+12[/tex]Knowing that a isn't zero. Let's start:
[tex]\begin{gathered} 5ax+3ax=8ax=4ax+12 \\ 8ax-4ax=12 \\ 4ax=12 \end{gathered}[/tex]Then, since a isn't zero we can divide the right side of the equation by 4a:
[tex]x=\frac{12}{4a}=\frac{3}{a}[/tex]So correct option is B.
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