Discover how IDNLearn.com can help you find the answers you need quickly and easily. Get thorough and trustworthy answers to your queries from our extensive network of knowledgeable professionals.
The given equation is,
[tex]2x^2+3x=2[/tex]Converting to the standard quadratic form, ax² + bx + c = 0, we have,
[tex]2x^2+3x-2=0[/tex]We have the solution for the quadratic equation as,
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Here,
[tex]\begin{gathered} a=2 \\ b=3 \\ c=-2 \end{gathered}[/tex]Substituting, we get,
[tex]\begin{gathered} x=\frac{-3\pm\sqrt[]{3^2-(4)(2)(-2)}}{2\times2} \\ =\frac{-3\pm\sqrt[]{9+16}}{4} \\ =\frac{-3\pm5}{4} \\ =\frac{-3+5}{4};\frac{-3-5}{4} \\ =\frac{1}{2};-2 \end{gathered}[/tex]