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how do you write an equation of the line that passes through the point (6,1) and the slope m=-3

Sagot :

Answer:

The equation of the line that passes through the point (6,1) and the slope m=-3​ is;

[tex]y=3x-17[/tex]

Explanation:

Given the line with slope;

[tex]m=3[/tex]

And passes through the point;

[tex](6,1)[/tex]

Using the point-slope form of linear equation;

[tex]y-y_1=m(x-x_1)[/tex]

Substituting the values of the slope and the given point;

[tex]y-1=3(x-6)[/tex]

Above is the point-slope form of the equation.

solving further to get the slope-intercept form of the equation we have;

[tex]\begin{gathered} y-1=3x-18 \\ y=3x-18+1 \\ y=3x-17 \end{gathered}[/tex]

Therefore, the equation of the line that passes through the point (6,1) and the slope m=-3​ is;

[tex]y=3x-17[/tex]

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