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5. Match each equation with the corresponding equation solved for a *

5 Match Each Equation With The Corresponding Equation Solved For A class=

Sagot :

Explanation

to solve an equation is to find its solutions, which are the values that fulfill the condition stated by the equation

so

Step 1

a)

[tex]\begin{gathered} a+2b=5 \\ \text{subtract 2b in both sides} \\ a+2b-2b=5-2b \\ a=5-2b \end{gathered}[/tex]

so

b)

[tex]\begin{gathered} 5a=2b \\ \text{divide both sides by 5} \\ \frac{5a}{5}=\frac{2b}{5} \\ a=\frac{2b}{5} \\ \text{hence} \\ 5a=2b\leftrightarrow a=\frac{2b}{5} \end{gathered}[/tex]

c)

[tex]\begin{gathered} a+5=2b \\ \text{subtract 5 in both sides} \\ a+5-5=2b-5 \\ a=2b-5 \\ so \\ a+5=2b\leftrightarrow a=2b-5 \end{gathered}[/tex]

d)

[tex]\begin{gathered} 5(a+2b)=0 \\ divide\text{ both sides by 5} \\ \frac{5(a+2b)}{5}=\frac{0}{5} \\ a+2b=0 \\ \text{subtract 2b in both sides} \\ a+2b-2b=0-2b \\ a=-2b \\ so \\ 5\mleft(a+2b\mright)=0\leftrightarrow a=-2b \end{gathered}[/tex]

e) finally

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