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Sagot :
For this case we have the following points given:
[tex](x_1=-2,y_1=0),(x_2=2,y_2=-4)[/tex]And the slope is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]And replacing we got:
[tex]m=\frac{-4-0}{2-(-2)}=\frac{-4}{4}=-1[/tex]The equation for the line is be given by:
[tex]0=-1(-2)+b[/tex][tex]b=-2[/tex]And the equation would be given by:
[tex]y=-x-2[/tex]And the intersection points would be:
x=0 y=-2. (y intercept)
y=0, x=-2. (x intercept)
The best answer would be:
B , C and D
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