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Sagot :
The zeroes of the function are the values of x which make it equal to zero
Since f(x) = (2x + 6)(x - 4)
Then to find the zeroes of f, equate f(x) by 0
[tex]\begin{gathered} f(x)=0 \\ (2x+6)(x-4)=0 \end{gathered}[/tex]Equate each bracket by 0 to find x
[tex]2x+6=0[/tex]Subtract 6 from each side
[tex]\begin{gathered} 2x+6-6=0-6 \\ 2x=-6 \end{gathered}[/tex]Divide both sides by 2
[tex]\begin{gathered} \frac{2x}{2}=\frac{-6}{2} \\ x=-3 \end{gathered}[/tex][tex]x-4=0[/tex]Add 4 to each side
[tex]\begin{gathered} x-4+4=0+4 \\ x=4 \end{gathered}[/tex]The zeroes of the function are x = -3 and x = 4
The answer is C
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