Get the information you need quickly and easily with IDNLearn.com. Get accurate answers to your questions from our community of experts who are always ready to provide timely and relevant solutions.
Sagot :
Given
[tex]\begin{gathered} 2x+3y=1470 \\ x\rightarrow\text{ number of sandwiches} \\ y\rightarrow\text{ number of wraps} \end{gathered}[/tex]1) Solve for y to find the slope-intercept form, as shown below
[tex]\begin{gathered} \Rightarrow3y=1470-2x \\ \Rightarrow y=\frac{1470}{3}-\frac{2x}{3} \\ \Rightarrow y=-\frac{2}{3}x+490 \end{gathered}[/tex]The slope-intercept form of the equation is y=-2x/3+490, where -2/3 is the slope and +490 is the y-intercept.
2) To graph the equation, start at (0,490), the y-intercept; then, move 3 units to the right for every 2 units down because the slope is -2/3.
For example, to the right of (0,490) we can find (0+3,490-2)=(3,488)
3) From part 1), notice that to the right of the equality there are only terms of x; then, we can rewrite it as shown below
[tex]\begin{gathered} y=f(x) \\ \Rightarrow f(x)=-\frac{2x}{3}+490 \end{gathered}[/tex]The graph of f(x) is the number of wraps as a function of the number of sandwiches (x).
4)
5)
The slope of the two lines will be the same since the ratio cost of a sandwich to the cost of a wrap stays the same; in contrast, the value of the y-intercept will be different because the total profit is now $1593 rather than $1470

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.