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The given expression is,
[tex]\frac{5x^2}{6y}\text{ --(1)}[/tex]a)
Put x=4 and y=10 in expression (1) and simplify.
[tex]\frac{5\times4^2}{6\times10}=\frac{5\times16}{60}=\frac{80}{60}=\frac{4}{3}[/tex]Therefore, when x=4 and y=10, the value of the given rational expression is 4/3.
b)
Put x=0 and y=11 in expression (1) and simplify.
[tex]\frac{5\times0}{6\times11}=0[/tex]Therefore, when x=0 and y=11, the value of the given rational expression is 0.