Let's put more details in the given figure to better understand the problem:
It appears that the triangle is an Isosceles Triangle. Because of this, the legs of the triangle should be congruent.
Let's determine the length of its leg using the Sine Function: Let, x = the length of the leg.
[tex]\text{ Sine }\Theta\text{ = }\frac{\text{ Opposite}}{\text{ Hypotenuse}}[/tex][tex]\text{ Sine }45^{\circ}\text{ = }\frac{\text{ x}}{\text{ 1}6}[/tex][tex]\text{ (16)Sine }45^{\circ}\text{ = x}[/tex][tex]\text{ x = (16)Sine }45^{\circ}[/tex][tex]\text{ x = (16)(}\frac{1}{\sqrt[]{2}})\text{ = }\frac{16}{\sqrt[]{2}}\text{ = }\frac{\text{ 16 }\cdot\text{ }\sqrt[]{2}}{\sqrt[]{2}\text{ }\cdot\text{ }\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}[/tex][tex]\text{ x = 8}\sqrt[]{2}[/tex]
Therefore, the length of its leg is 8√2
