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For a normal distribution, it is known that the mean is zero and the standard deviation is 1Be sure to draw and label a normal distribution for each problem. Find the probability that a z score is above 1.68.

Sagot :

[tex]\begin{gathered} Z=\frac{X-\mu}{\sigma} \\ Z=1.68 \\ so\colon \\ 1.68=\frac{X-0}{1} \\ so\colon \\ X=1.68 \\ P(X>1.68)\approx0.0465 \end{gathered}[/tex]

Answer:

0.0465 or 4.65%

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