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Sagot :
Answer:
Explanations:
Given the following parameters;
Mean = 78
Standard deviation = 4
If a randomly selected student with a score between 71 and 85, then we need the probability P(71
Determine the z-score for each score
For a score of 71
[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ z=\frac{71-78}{4} \\ z=-\frac{7}{4} \\ z_1=-1.75 \\ \end{gathered}[/tex]For a score of 85
[tex]\begin{gathered} z_2=\frac{85-78}{4} \\ z_2=\frac{7}{4} \\ z_2=1.75 \end{gathered}[/tex]Determine the probability for the z-score values P(-1.75 < z < 1.75) using the standard table.
[tex]\begin{gathered} P(-1.75Hence the percentage of scores for a randomly selected student with a score between 71 and 85 is 91.98%
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