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Given expression is,
[tex]32^{x-1}=16^{x+4}[/tex]let us simplify,
[tex]\begin{gathered} \log (32^{x-1})=\log (16^{x+4}) \\ (x-1)(\log (32))=(x+4)(\log (16)) \\ x-1=\frac{\log(16)}{\log(32)}\cdot x+4 \\ x-1=0.8\cdot(x+4) \\ x-1=0.8x+3.2 \\ x-0.8x=3.2+1 \\ 0.2x=4.2 \\ x=\frac{4.2}{0.2} \\ x=21 \end{gathered}[/tex]The answer is 21.