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CH4 (g)+ 202(g)=CO2(g) + 2H2O(l)If 133.2 grams of CH4 react with excess O2 , how many grams of H2O result?

Sagot :

299.7g of H2O will be produced.

1st) With the balanced chemical equation and the molar mass of CH4 and H2O, we can calculate the amount of H2O that is produced by stoichiometry:

- CH4 molar mass: 16g/mol

- H2O molar mass: 18g/mol

According to the balanced equation, 16g of CH4 will produce 36g of H2O (2 x 18g).

2nd) Now, with a mathematical rule of three we can calculate the grams of water that will be produced from 133.2 grams of CH4:

[tex]\begin{gathered} 16gCH_4-36gH_2O \\ 133.2gCH_4-x=\frac{133.2gCH_4\cdot36gH_2O}{16gCH_4} \\ x=299.7gH_2O \end{gathered}[/tex]

Finally, 299.7g of H2O will be produced from 133.2 grams of CH4.

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