a)The formula for calculating force is expressed as
F = mg
Since the truck is inclined, the force required to keep the truck from rolling down the hill is
F = WSinθ
where
W is the weight
θ is the angle of inclination
From the information given,
W = 22000 pounds
θ = d
Force required to keep the truck from rolling down the hill = 22000 x Sind
F = 22000Sind lb
b) We would substitute each angle for d. We have
1) d = 0
F = 22000Sin0
F = 0 lb
2) d = 1
F = 22000Sin1
F = 384 lb
3) d = 2
F = 22000Sin2
F = 767.8 lb
4) d = 3
F = 22000Sin3
F = 1151.4 lb
5) d = 4
F = 22000Sin4
F = 1534.6 lb
F = 1534.6 lb
6) d = 5
F = 22000Sin5
F = 1917.4 lb
7) d = 6
F = 22000Sin6
F = 2300 lb
8) d = 7
F = 22000Sin7
F = 2681.1 lb
9) d = 8
F = 22000Sin8
F = 3061.8 lb
10) d = 9
F = 22000Sin9
F = 3441.6 lb
11) d = 10
F = 22000Sin10
F = 3820.3 lb
b) Force perpendicular to the hill is
F = WCosd
when d = 2
F = 22000Cos2
F = 21986.6 lb
