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Sagot :
1) Write the chemical equation.
[tex]H_2SO_{4(aq)}+2LiOH\rightarrow2H_2O+Li_2SO_4[/tex]2) List the known and unknown quantities.
Sample: H2SO4
Volume: 33.98 mL.
Concentration: unknown
Titrant: LiOH
Volume: 18.19 mL = 0.01819
Concentration: 1.35 M
3) Find moles of LiOH
3.1- Set the equation
[tex]M=\frac{moles\text{ }of\text{ }solute}{liters\text{ }of\text{ }solution}[/tex]3.2- Plug in the values
[tex]1.35\text{ }M=\frac{moles\text{ }of\text{ }solute}{0.01819\text{ }L}[/tex][tex]moles\text{ }of\text{ }solute=1.35\text{ }M*0.01819\text{ }L[/tex][tex]moles\text{ }LiOH=0.0245565[/tex]The number of moles of LiOH in the reaction is 0.0246.
4) Find moles of H2SO4
The molar ratio between H2SO4 and LiOH is 1 mol H2SO4: 2 mol LiOH.
[tex]mol\text{ }H_2SO_4=0.0246\text{ }mol\text{ }LiOH*\frac{1\text{ }mol\text{ }H_2SO_4}{2\text{ }mol\text{ }LiOH}[/tex][tex]mol\text{ }H_2SO_4=0.01228\text{ }mol\text{ }H_2SO_4[/tex]5) Molarity of H2SO4
Sample: H2SO4
Moles: 0.01228
Volume: 33.98 mL.
5.1- Convert mL to L.
1 L = 1000 mL
[tex]L=33.98\text{ }mL*\frac{1\text{ }L}{1000\text{ }mL}=0.03398\text{ }L[/tex]5.2- Set the equation to find molarity.
[tex]M=\frac{moles\text{ }of\text{ }solute}{liters\text{ }of\text{ }solution}[/tex][tex]M=\frac{0.01228\text{ }mol\text{ }H_2SO_4}{0.03398\text{ }L}[/tex][tex]M=0.3614\text{ }M[/tex]The molarity of the sample is 0.3614 M H2SO4.
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