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Sagot :
The equation of a line can be found by using the following expression:
[tex]y(x)=\frac{y_2-y_1}{x_2-x_1}\cdot x+b[/tex]Where (x1, y1) and (x2, y2) are known points on the line and b is the y-intercept.
The y-intercept is the value at which the line crosses the y-axis, this value has a correspondent x-coordinate of 0. To find it we need to look at the table and find which value of y has a x coordinate equal to 0, this value is 3. The y-intercept is equal to 3.
To calculate the slope we need two points we will choose (1,1) and (0,3). Applying these points on the expression we can find the slope:
[tex]m=\frac{1-3}{1-0}=\frac{-2}{1}=-2[/tex]The slope of the line is -2.
With the slope and y-intercept we can determine the equation of the line, which is:
[tex]y(x)=-2\cdot x+3[/tex]
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