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The domain of a function is all values of x the function can assume.
Since this function has a fraction, and any fraction can't have a denominator equal to 0, we have the following condition:
[tex]\begin{gathered} x^2-2x-15\ne0 \\ x\ne\frac{2\pm\sqrt[]{4+60}}{2} \\ x\ne\frac{2\pm8}{2} \\ x\ne5,x\ne-3 \end{gathered}[/tex]The variable x can be any real number, except -3 and 5, therefore the domain set is:
[tex](-\text{inf,}-3)\cup(-3,5)\cup(5,\text{inf)}[/tex]