Let the price of a bike at Store B be k
The price of a bike at Store A is 5/6 of the price at store B, which means
[tex]=\frac{5}{6}\times k=\frac{5k}{6}[/tex]
If the price of a bike at Store A is $150.60, i.e
[tex]\frac{5k}{6}=150.60[/tex]
Solve to find k, i.e the price of a bike at Store B
Crossmultiply
[tex]\begin{gathered} \frac{5k}{6}=150.60 \\ 5k=150.60\times6=903.6 \\ 5k=903.6 \\ \text{Divide both sides by 5} \\ \frac{5k}{5}=\frac{903.6}{5} \\ k=\text{ \$180.72} \end{gathered}[/tex]
The price of a bike at store B is k = $180.72
The amount saved if the bike is bought at Store A is
[tex]=180.72-150.60=\text{ \$30.12}[/tex]
Hence, the amount saved by buying the bike at Store A is $30.12
