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Sagot :
Given:
Two planes leave from Atlanta, Georgia.
One makes a 7.4 hours flight to Seattle, Washington and the other makes a 2.6 hours flight to Boston, Massachusetts.
The plane to Boston averages 60 mph slower than the plane to Seattle.
The total distance traveled by both plan is 3125 mi.
Required:
We need to find the Average speed of each plane
Explanation:
Speed of Seattle plane is S
Speed of Boston plane is B
by The plane to Boston averages 60 mph slower than the plane to Seattle
we can say that
[tex]B=S-60[/tex]Formula of distance is the rate of speed times time
[tex]d=rt[/tex]Where d is distance
r is rate of speed
t it time
Now total distance traveled by both plane is 3124 mi
so
[tex]3124=7.4S+2.6B[/tex]substitute the value of B
[tex]\begin{gathered} 3124=7.4S+2.6(S-60) \\ 3124=7.4S+2.6S-156 \\ 3280=10S \\ 328=S \end{gathered}[/tex]Now to find B
[tex]\begin{gathered} B=S-60 \\ B=328-60 \\ B=268 \end{gathered}[/tex]Final answer:
Average speed of S is 328 mph
Average speed of B is 268 mph
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