Answered

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A 62.92 microC charge is fixed at the origin. How much work would be required to place a 7.21 microC charge 8.57 cm from this charge ?

Sagot :

Given

The fixed charge is q=62.92 mC

The other charge is q'=7.21 mC

The distance is r=8.57 cm=0.0857 m

To find

The work done

Explanation

The potential is

[tex]\begin{gathered} V=\frac{kq}{r} \\ \Rightarrow V=9\times10^9\frac{62.92\times10^{-6}}{0.0857} \\ \Rightarrow V=6.6\times10^6V \end{gathered}[/tex]

Work done is

[tex]\begin{gathered} W=q^{\prime}V \\ \Rightarrow W=7.21\times10^{-6}\times6.6\times10^6=47.586\text{ J} \end{gathered}[/tex]

Conclusion

The work done is 47.586 V

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