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Explanation:
We are given: volume = 4 L constant
: Initial temperature = 296K
: Initial pressure = 130kPa
: Final pressure = 380kPa
To find the final temperature, we use:
[tex]\begin{gathered} \frac{P_1}{T_1}\text{ = }\frac{P_2}{T_2} \\ \\ \therefore T_2\text{ = }\frac{P_2T_1}{P_1}\text{ = }\frac{380\text{ }\times\text{ 296}}{130}\text{ = 865.2K} \end{gathered}[/tex]