IDNLearn.com connects you with a community of experts ready to answer your questions. Discover reliable and timely information on any topic from our network of knowledgeable professionals.
∠EFH and ∠HFG are complementary angles, which are two angles whose sum is exactly 90⁰, therefore:
[tex]\begin{gathered} m\angle EFH+m\angle HFG=90 \\ so\colon \\ 66+m\angle HFG=90 \\ m\angle HFG=90-66 \\ m\angle HFG=24^{\circ} \end{gathered}[/tex]