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A student has a 6.99 liters of a solution that has a molarity of 2.87 M. How many moles of solute are present in this solution? Round your answer to the nearest 0.01 and include units properly abbreviated, but NOT substance!

Sagot :

The equation for the molarity, or molar concentration, is:

[tex]C=\frac{n_{\text{solute}}}{V_{\text{solution}}}[/tex]

Where C is the molarity, n is the number of moles of solute and V is the volume of solution.

Since we know the molarity and the volume of solution, we can calculate the number of moles of solute:

[tex]\begin{gathered} V_{\text{solution}}=6.99L \\ C=2.87M=2.87mol\/L \\ n_{\text{solute}}=C\cdot V_{\text{solution}} \\ n_{\text{solute}}=2.87mol\/L\cdot6.99L=20.0613mol\approx20.06mol \end{gathered}[/tex]

So, there is approximately 20.06 mol in the solution.

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