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EXPLANATION
The slope of a line is also the tangent of the angle between the positive x and the line
Hence
[tex]\begin{gathered} \tan \theta=\frac{3}{4} \\ \tan \theta=0.75 \end{gathered}[/tex]then, we have that
[tex]\begin{gathered} \theta=\tan ^{-1}(0.75)=36.8698 \\ \theta=36.9^0 \end{gathered}[/tex]Therefore the angle of inclination θ=36.9° to the nearest tenth
The third option is correct