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What would be the period of an oscillating spring that has a mass of 1.92 kg attached to it if the spring constant has a value of 0.800 N/m?15.1 s9.73s2.62 s4.06 s

Sagot :

Given:

The mass is m = 192 kg

The value of the spring constant is k = 0.8 N/m

To find the time period.

Explanation:

The time period can be calculated by the formula

[tex]T\text{ = 2}\pi\sqrt{\frac{m}{k}}[/tex]

On substituting the values, the time period will be

[tex]\begin{gathered} T=2\times3.14\times\sqrt{\frac{1.92}{0.8}} \\ =9.73\text{ s} \end{gathered}[/tex]

Final Answer: The time period is 9.73 s