Connect with a knowledgeable community and get your questions answered on IDNLearn.com. Join our Q&A platform to receive prompt and accurate responses from knowledgeable professionals in various fields.

What would be the period of an oscillating spring that has a mass of 1.92 kg attached to it if the spring constant has a value of 0.800 N/m?15.1 s9.73s2.62 s4.06 s

Sagot :

Given:

The mass is m = 192 kg

The value of the spring constant is k = 0.8 N/m

To find the time period.

Explanation:

The time period can be calculated by the formula

[tex]T\text{ = 2}\pi\sqrt{\frac{m}{k}}[/tex]

On substituting the values, the time period will be

[tex]\begin{gathered} T=2\times3.14\times\sqrt{\frac{1.92}{0.8}} \\ =9.73\text{ s} \end{gathered}[/tex]

Final Answer: The time period is 9.73 s

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.