Answered

Connect with experts and get insightful answers on IDNLearn.com. Join our Q&A platform to receive prompt and accurate responses from knowledgeable professionals in various fields.

You roll two regular six-sided dice. Which event is more likely: A. You roll seven (i.e., the dice add up to seven). B. You roll doubles (i.e., both dice show the same number). Show or explain your thinking.

Sagot :

Given:

A regular six-sided dice.

The probability of each number = 1/6

You roll two regular six-sided dice.

If we calculate the probability of the dice add up to seven

The seven will come for the following events

1 + 6

2 + 5

3 + 4

4 + 3

5 + 2

6 + 1

So, the total probability =

[tex]7\cdot(\frac{1}{6})^2=\frac{7}{36}[/tex]

Now, calculate the probability when both dice show the same number

So, the events will be:

1 + 1

2 + 2

3 + 3

4 + 4

5 + 5

6 + 6

So, the total probability =

[tex]6\cdot(\frac{1}{6})^2=\frac{6}{36}[/tex]

By comparing the results:

[tex]\frac{7}{36}>\frac{6}{36}[/tex]

So, the answer will be the event that is more like is:

A. You roll seven

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.