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Sagot :
Find the total surface area of a cylinder that has a diameter of 4.7 m and a height 12 m​
we know that
the surface area of a cylinder is equal to
[tex]SA=2\pi r^2+2\pi rh[/tex]where
r is the radius of the circular base
h is the height of cylinder
In this problem we have
r=D/2 -----> teh radius is half the diameter
r=4.7/2
r=2.35 m
h=12 m
substitute the given values
[tex]\begin{gathered} SA=2\pi(2.35)^2+2\pi(2.35)(12) \\ SA=11.045\pi+56.4\pi \\ SA=67.445\pi\text{ m\textasciicircum{}2} \end{gathered}[/tex]therefore
the surface area is equal to
SA=67.445pi square meters
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