IDNLearn.com: Where your questions meet expert answers and community support. Discover reliable and timely information on any topic from our network of experienced professionals.
Sagot :
Given in the question:
a.) One aquarium contains 2.1 cubic feet of water.
b.) The other aquarium contains 1.4 cubic feet of water.
c.) The water in the larger aquarium weighs 43.68 pounds more than the water in the smaller aquarium.
To be able to answer this type of problem, we will be applying the ratio and proportion:
We get,
[tex]\frac{Wt\text{. of Large Aquarium}}{Volume\text{ of Large Aquarium}}\text{ = }\frac{Wt.\text{ of Small Aquarium}}{Volume\text{ of Small Aquarium}}[/tex][tex]\text{ }\frac{\text{ w + 43.68 lbs.}}{2.1ft.^3}\text{ =}\frac{\text{ w}}{1.4ft.^3}\text{ }\rightarrow\text{ }\frac{w\text{ + 43.68}}{2.1}\text{ = }\frac{w}{1.4}[/tex][tex]\frac{w\text{ + 43.68}}{2.1}\text{ = }\frac{w}{1.4}[/tex][tex](w\text{ + 43.68)}(1.4)\text{ = (}w)(2.1)[/tex][tex]\text{ 1.4w + }61.152\text{ = 2.1w}[/tex][tex]\text{2.1w = 1.4w + }61.152[/tex]Therefore, the equation is 2.1w = 1.4w + 61.152
Let's determine the value of w:
[tex]\text{2.1w = 1.4w + }61.152[/tex][tex]\text{2.1w - 1.4w = }61.152[/tex][tex]0.7\text{w = }61.152[/tex][tex]\frac{0.7\text{w }}{0.7}\text{= }\frac{61.152}{0.7}[/tex][tex]\text{ w = }87.36\text{ lbs.}[/tex]Let's determine the weight of 1 cubic foot of water:
[tex]\text{ Wt. of 1 ft}^3\text{ of water = }\frac{Wt.\text{ of Small Aquarium}}{Volume\text{ of Small Aquarium}}[/tex][tex]\text{ = }\frac{87.36\text{ lbs.}}{1.4ft.^3}[/tex][tex]\text{ = }62.4lbs./ft^3[/tex]Therefore, the weight of 1 cubic foot of water is 62.4 lbs.
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.
