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In the accompanying diagram, mZC = 90, mZA = 42, and CA = 10. Which equation can be used to find AB? A B 10 tan 42° = AB

In The Accompanying Diagram MZC 90 MZA 42 And CA 10 Which Equation Can Be Used To Find AB A B 10 Tan 42 AB class=

Sagot :

We have to find AB.

As we have a right triangle, we can use trigonometric ratios to relate trigonometric functions with the length of the sides.

In this case, we use the angle [tex]\begin{gathered} \cos (\alpha)=\frac{\text{Adyacent}}{\text{Hypotenuse}} \\ \cos (A)=\cos (42\degree)=\frac{AC}{AB}=\frac{10}{AB} \\ \cos (42\degree)=\frac{10}{AB} \end{gathered}[/tex]Answer:

cos(42º)=10/AB [Option D]