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Solve for x. The triangles in each pair are similar.1) PQR - PFG2) ABC - AVW

Solve For X The Triangles In Each Pair Are Similar1 PQR PFG2 ABC AVW class=

Sagot :

Remember that

If two triangles are similar, then the artio of its corresponding sides is proportional

so

Part 1

triangle PQR and PFG are similar

that means

PQ/PF=PR/PG

substitute the given values

27/(2x-9)=27/(9)

so

2x-9=9

2x=18

x=9

Part 2

we have

triangle ABC is similar to triangle AVW

that means

AB/AV=AC/AW

substitute the given values

182/(10x+5)=196/(70)

solve for x

182*70=(10x+5)*196

12,740=1,960x+980

1,960x=12,740-980

1,960x=11,760

x=6

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