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Sagot :
Answer:
B. The zeros are -2/3 and -3 because y=(3x+2)(x+3)
Explanation:
Given the equation:
[tex]y=3x^2+11x+6[/tex]To find the zeros, first, factorize the expression:
[tex]\begin{gathered} y=3x^2+9x+2x+6 \\ y=3x(x+3)+2(x+3) \\ y=(3x+2)(x+3) \end{gathered}[/tex]Next, set the factored expression equal to 0.
[tex]\begin{gathered} y=(3x+2)(x+3)=0 \\ \implies3x+2=0\text{ or }x+3=0 \\ 3x=-2\text{ or }x=-3 \\ x=-\frac{2}{3}\text{ or }x=-3 \end{gathered}[/tex]Thus, the zeros are -2/3 and -3 because y=(3x+2)(x+3).
The correct choice is B.
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