[tex]Pr(\text{2 heavy smokers) = }0.007531[/tex]Explanation:[tex]\begin{gathered} \text{Total smokers from the table = 991} \\ \text{Total }nu\text{mber of heavy smokers = 86} \\ \\ \text{probability of picking two heavy smokers = Pr(heavy smoker and heavy smoker)} \end{gathered}[/tex][tex]Pr(\text{heavy smoker) = }\frac{Total\text{ }number\text{ of heavy smoker}}{\text{total smokers}}[/tex][tex]\begin{gathered} Pr(\text{heavy smoker) = }\frac{86}{991} \\ \\ Pr(\text{2 heavy smokers) = }Pr(\text{heavy smoker) }\times\text{ }Pr(\text{heavy smoker)} \end{gathered}[/tex][tex]\begin{gathered} Pr(\text{2 heavy smokers) = }\frac{86}{991}\times\frac{86}{991} \\ Pr(\text{2 heavy smokers) =}\frac{7396}{982081} \\ Pr(\text{2 heavy smokers) = }0.007531\text{ (6 decimal place)} \end{gathered}[/tex]
