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The distance h a body will move in a free fall is expressed by the formula h=1/2 gt2 if g =980 cm per sec2 and t= 20 sec, the distance h is

Sagot :

Solution

Given the distance h as

[tex]h=\frac{1}{2}t^2[/tex]

Here,

[tex]\begin{gathered} g=980\text{ cm/sec}^2 \\ \\ t=20\text{ sec} \end{gathered}[/tex]

Therefore, the distance h is: 196000 cm

[tex]h=\frac{1}{2}\times980\times20^2=196000\text{ cm}[/tex]

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