Answered

IDNLearn.com makes it easy to find accurate answers to your questions. Get prompt and accurate answers to your questions from our community of experts who are always ready to help.

Two identical strings making an angle of 0= 26.3 degree with respect to the vertical support a block of mass m=13.7 Kg what is the tension in each of the strings ?

Two Identical Strings Making An Angle Of 0 263 Degree With Respect To The Vertical Support A Block Of Mass M137 Kg What Is The Tension In Each Of The Strings class=

Sagot :

The free-body diagram of the configuration shown is the following:

Now, we add the forces in the vertical direction:

[tex]\Sigma F_v=T_y+T_y-mg[/tex]

Since the system is in equilibrium the sum of forces in the vertical direction is zero:

[tex]T_y+T_y-mg=0[/tex]

Now, we add like terms:

[tex]2T_y-mg=0[/tex]

Now, the y-component of the tension is determined using the following right triangle:

Now, we use the trigonometric function cosine:

[tex]cos(26.3)=\frac{T_y}{T}[/tex]

Now, we multiply both sides by "T":

[tex]Tcos(26.3)=T_y[/tex]

Now, we substitute in the sum of vertical forces:

[tex]2Tcos(26.3)-mg=0[/tex]

Now, we solve for "T". First, we add "mg" to both sides:

[tex]2Tcos(26.3)=mg[/tex]

Now, we divide both sides by "2cos(26.3)":

[tex]T=\frac{mg}{2cos(26.3)}[/tex]

Now, we plug in the values of mass and the acceleration of gravity:

[tex]T=\frac{(13.7kg)(9.8\frac{m}{s^2})}{2cos(26.3)}[/tex]

Now, we solve the operations:

[tex]T=74.88N[/tex]

Therefore, the tension is 74.88 Newton

View image TremonG78141
View image TremonG78141
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.