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4. Line G: 3x + 2y=10Line H: y= -3/2x - 5

Sagot :

Answer:

Explanation:

If Lines G and H are perpendicular to each other then the slope of one must be negative reciprocals of the slope of the other.

In other words,

The slope of line H = -1 / slope of line G.

Now, what is the slope of line G?

To find out, we first have to write the line in slope-intercept form ( y = mx + b).

Now, subtracting 3x from both sides of the equation gives

[tex]3x+2y-3x=10-3x[/tex][tex]2y=10-3x[/tex]

dividing both sides by 2 gives

[tex]y=\frac{10-3x}{2}[/tex][tex]y=5-\frac{3}{2}x[/tex]

This tells us that the slope of line G is -3/2 x.