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Sagot :
Answer
2C → 3A + 4B ΔG°rxn = 421.0 kJ/mol
Explanation
Given that:
C → 3/2A + 2B ΔG°rxn = 210.5 kJ/mol
To get the ΔG°rxn for the given reaction; 2C → 3A + 4B, just multiply C → 3/2A + 2B ΔG°rxn = 210.5 kJ/mol by 2, we have:
2 x 1C → 2 x 3/2A + 2 x 2B ΔG°rxn = 2 x 210.5 kJ/mol
2C → 3A + 4B ΔG°rxn = 421.0 kJ/mol
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