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Sagot :
given the sample space;
Probability of getting even number equals
[tex]\begin{gathered} Pr(even\text{ number) = }\frac{number\text{ of possible outcome}}{Total\text{ outcome}} \\ Pr(even\text{ number = }\frac{3}{6} \\ Pr(even\text{ number }=\frac{1}{2}\text{ } \end{gathered}[/tex]Probability of arrow stoping on blue is
[tex]\begin{gathered} Pr(\text{ arrow stoping on blue) = }\frac{number\text{ of posible outcome}}{\text{Total outcome}} \\ Pr(\text{ arrow stoping on blue) = }\frac{1}{3} \end{gathered}[/tex]Therefore the probability of getting even number and the arow stoping on blue is
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