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Answer:
Given that,
To solve,
3(1/6+9)=1/2−27.
That is, To find the value of x
we get,
[tex]3\mleft(\frac{1}{6}+9\mright)=\frac{1}{2}-27.[/tex][tex]\frac{3}{6}x+27=\frac{1}{2}x-27[/tex]we get,
[tex]\frac{1}{2}x+27=\frac{1}{2}x-27[/tex][tex]\frac{1}{2}x-\frac{1}{2}x+27=-27[/tex][tex]27=-27[/tex]Since the x term is got cancelled, There is no solution for this equation.
Answer is: option D: no solution.