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I need help finding the Xs on this question....thank you

I Need Help Finding The Xs On This Questionthank You class=

Sagot :

In order to find the zeros of this quadratic function, we can use the quadratic formula:

[tex]\begin{gathered} x_1=\frac{-b+\sqrt[]{b^2-4ac}}{2a} \\ x_2=\frac{-b-\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]

Using the given values of a = 3, b = 16 and c = -12, we have:

[tex]\begin{gathered} x_1=\frac{-16+\sqrt[]{256+144}}{2\cdot3}=\frac{-16+20}{6}=\frac{2}{3} \\ x_2=\frac{-16-20}{6}=-6 \end{gathered}[/tex]

So the values of x that make this equation be equal zero are x = 2/3 and x = -6.

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