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ANSWER
[tex]\begin{equation*} 0.0588 \end{equation*}[/tex]EXPLANATION
A standard deck of cards has 52 cards.
The number of king is 4
The probability of choosing the first king is;
[tex]\begin{gathered} P(K_1)=\frac{n(K)}{n(cards)} \\ =\frac{4}{52} \end{gathered}[/tex]The probability of choosing king again without replacement i;
[tex]P(K_2)=\frac{3}{51}[/tex]Hence the probability of K2 AND K1 is;
[tex]\begin{gathered} P(\frac{K_1}{K_2})=\frac{P(K_1)\times P(K_2)=}{P(K_1)} \\ =\frac{\frac{4}{52}\times\frac{3}{51}}{\frac{4}{52}} \\ =\frac{3}{51} \\ =0.0588 \end{gathered}[/tex]
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