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We have this first condition given:
[tex]x+y=\text{ 10 (1)}[/tex]And the second one:
[tex]x-2y=\text{ 8 (2)}[/tex]If we solve for x from equation (1) we got:
[tex]x=\text{ 10}-y\text{ (3)}[/tex]And if we solve for x from equation (2) we got:
[tex]x=\text{ 8+2y (4)}[/tex]Now we can set equal equations (3) and (4)
[tex]10-y=\text{ 8+2y}[/tex]And solving for y we got:
[tex]18=\text{ 3y }\rightarrow\text{ y= }\frac{18}{3}=\text{ 6}[/tex]Final answer:
[tex]y=\text{ 3}\cdot6\text{ = 18}[/tex]