Answered

IDNLearn.com: Your go-to resource for finding precise and accurate answers. Get accurate and detailed answers to your questions from our knowledgeable and dedicated community members.

Construct a polar equation for the conic section with the focus at the originand the following eccentricity and directrix.ConicEccentricityDirectrixparabolae=X =

Construct A Polar Equation For The Conic Section With The Focus At The Originand The Following Eccentricity And DirectrixConicEccentricityDirectrixparabolaeX class=

Sagot :

Given:

Here the eccentricity and directrix are 1 and -1/3 respectively of parabola .

Required:

We have to construct a polar equation for the parabola

Explanation:

Formula to construct the polar equation is

[tex]\Gamma=\frac{ep}{1+ecos\emptyset}[/tex][tex]\Gamma=\frac{1*\frac{1}{3}}{1+1cos\emptyset}[/tex][tex]\Gamma=\frac{1}{3+3cos\emptyset}[/tex]

Final answer:

[tex]\Gamma=\frac{1}{3+3cos\emptyset}[/tex]

is the polar equation for given information.

View image NovalieF473848
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.